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AndYieldsB
⊢
f
1
g
⊃
(
f
∧
f
1
)
g
AndYieldsB
Proof:
1
⊢
f
∧
f
1
⊃
f
1
Prop
2
⊢
f
1
g
⊃
(
f
∧
f
1
)
g
1
,
LeftYieldsImpYields
qed
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2023-09-12
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