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AndYieldsA
⊢
f
g
⊃
(
f
∧
f
1
)
g
AndYieldsA
Proof:
1
⊢
f
∧
f
1
⊃
f
Prop
2
⊢
f
g
⊃
(
f
∧
f
1
)
g
1
,
LeftYieldsImpYields
qed
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2024-08-03
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