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ChopEmptyOrImpRule
⊢
g
⊃
empty
∨
g
1
⇒ ⊢
f
;
g
⊃
f
∨
(
f
;
g
1
)
ChopEmptyOrImpRule
Proof:
1
⊢
g
⊃
empty
∨
g
1
given
2
⊢
f
;
g
⊃
(
f
;
empty
)
∨
(
f
;
g
1
)
1
,
ChopOrImpRule
3
⊢
f
;
empty
≡
f
ChopEmpty
4
⊢
f
;
g
⊃
f
∨
(
f
;
g
1
)
2
,
3
,
Prop
qed
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2024-08-03
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