CSIntro

f more (g more) ; f ⇒ ⊢ f g CSIntro

Proof:

1
f more (g more) ; f
given
2
more ≡¬empty
3
f ∧¬empty (g more) ; f
1, 2,Prop
4
gempty (g more) ; g
5
f ∧¬g(g more) ; f ∧¬((g more) ; g)
3, 4,Prop
6
g more more
7
f g

qed

2023-09-12
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