ChopPlusImpChopPlus

⊢ f ⊃ g ⇒ ⊢ f+ ⊃ g+ ChopPlusImpChopPlus

Proof:

1
⊢ f ⊃ g
given
2
⊢ f+ ≡ f ∨ (f ∧more) ; f+
3
⊢ g+ ≡ g ∨ (g ∧more) ; g+
4
⊢ f+ ∧¬(g+) ⊃ ((f ∧more) ; f+) ∧¬((g ∧more) ; g+)
1, 2, 3,Prop
5
⊢ f ∧more ⊃ g ∧more
1,Prop
6
⊢ (f ∧more) ; f+ ⊃ (g ∧more) ; f+
7
⊢ f+ ∧¬(g+) ⊃ ((g ∧more) ; f+) ∧¬((g ∧more) ; g+)
4, 6,Prop
8
⊢ g ∧more ⊃more
9
⊢ f+ ⊃ g+

qed

2024-08-03
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