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BaChopImpChopBa
⊢
f
⊃
g
;
g
1
⊃
g
; (
f
∧
g
1
)
BaChopImpChopBa
Proof:
1
⊢
f
⊃
(
g
1
⊃
f
∧
g
1
)
PTL
2
⊢
(
g
1
⊃
f
∧
g
1
)
⊃
g
;
g
1
⊃
g
; (
f
∧
g
1
)
BaRightChopImpChop
3
⊢
f
⊃
g
;
g
1
⊃
g
; (
f
∧
g
1
)
1
,
2
,
Prop
qed
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2023-09-12
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