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BaRightChopImpChop
⊢
(
g
⊃
g
1
)
⊃
f
;
g
⊃
f
;
g
1
BaRightChopImpChop
Proof:
1
⊢
(
g
⊃
g
1
)
⊃
(
g
⊃
g
1
)
BaImpBt
2
⊢
(
g
⊃
g
1
)
⊃
f
;
g
⊃
f
;
g
1
BoxChopImpChop
3
⊢
(
g
⊃
g
1
)
⊃
f
;
g
⊃
f
;
g
1
1
,
2
,
Prop
qed
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2023-09-12
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