CSEqvCS

⊢ f ≡ g ⇒ ⊢ f∗≡ g∗ CSEqvCS

Proof:

1
⊢ f ≡ g
given
2
⊢ f+ ≡ g+
3
⊢ empty ∨ f+ ≡empty ∨ g+
2,Prop
4
⊢ f∗≡ g∗
3, def. of ∗

qed

2024-08-03
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