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BaGen
⊢
f
⇒ ⊢
f
BaGen
Proof:
1
⊢
f
given
2
⊢
f
1
,
BoxGen
3
⊢
f
2
,
BiGen
4
⊢
f
≡
f
BaEqvBiBt
5
⊢
f
⊃
f
4
,
Prop
6
⊢
f
3
,
5
,
MP
qed
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2023-09-12
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