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DiAndImpAnd
⊢
(
f
∧
g
)
⊃
f
∧
g
DiAndImpAnd
Proof:
1
⊢
(
f
∧
g
)
⊃
f
DiAndA
2
⊢
(
f
∧
g
)
⊃
g
DiAndB
3
⊢
(
f
∧
g
)
⊃
f
∧
g
1
,
2
,
Prop
qed
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2023-09-12
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