FiniteImpBfImpBfRule

finite (f g) ⇒ ⊢ f g FiniteImpBfImpBfRule

Proof:

1
finite (f g)
Assump
2
(f g)
3
(f g) ( f g)
4
f g
2, 3,MP

qed

2023-09-12
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