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FiniteImpBfImpBfRule
⊢
finite
⊃
(
f
⊃
g
)
⇒ ⊢
f
⊃
g
FiniteImpBfImpBfRule
Proof:
1
finite
⊃
(
f
⊃
g
)
Assump
2
(
f
⊃
g
)
1
,
BfFGen
3
(
f
⊃
g
)
⊃
(
f
⊃
g
)
BfImpDist
4
f
⊃
g
2
,
3
,
MP
qed
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2023-09-12
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