Next
Prev
Up
DfDiamondEqvDiamondDf
⊢
f
≡
f
DfDiamondEqvDiamondDf
Proof:
1
(
true
⌢ f
)
⌢
true
≡
true
⌢
(
f ⌢
true
)
ChopAssoc
2
(
f
)
⌢
true
≡
(
f ⌢
true
)
1
,
def. of
3
f
≡
f
2
,
def. of
qed
Next
Prev
Up
2023-09-12
Contact
|
Home
|
ITL home
|
Course
|
Proofs
|
Algebra
|
FL
© 1996-2023