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DfDiamondEqvDiamondDf
⊢
f
≡
f
DfDiamondEqvDiamondDf
Proof:
1
(
true
⌢ f
)
⌢
true
≡
true
⌢
(
f ⌢
true
)
ChopAssoc
2
(
f
)
⌢
true
≡
(
f ⌢
true
)
1
,
def. of
3
f
≡
f
2
,
def. of
qed
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2024-08-03
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