ChopAndNotChopImp

f ⌢ g ∧¬(f ⌢ g1) f ⌢ (g ∧¬g1) ChopAndNotChopImp

Proof:

1
g (g ∧¬g1) g1
2
f ⌢ g f ⌢ (g ∧¬g1) f ⌢ g1
3
f ⌢ g ∧¬(f ⌢ g1) f ⌢ (g ∧¬g1)
2,Prop

qed

2023-09-12
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