DfOrEqv

⊢ (f ∨ g) ≡ f ∨ g DfOrEqv

Proof:

1
(f ∨ g) ⌢ true ≡ (f ⌢ true) ∨ (g ⌢ true)
2
(f ∨ g) ≡ f ∨ g
1, def. of 

qed

2024-08-03
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