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DfOrEqv
⊢
(
f
∨
g
)
≡
f
∨
g
DfOrEqv
Proof:
1
(
f
∨
g
)
⌢
true
≡
(
f ⌢
true
)
∨
(
g ⌢
true
)
OrChopEqv
2
(
f
∨
g
)
≡
f
∨
g
1
,
def. of
qed
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2023-09-12
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