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BfImpBfRule
⊢
f
⊃
g
⇒ ⊢
f
⊃
g
BfImpBfRule
Proof:
1
f
⊃
g
Assump
2
(
f
⊃
g
)
1
,
BfGen
3
(
f
⊃
g
)
⊃
(
f
)
⊃
(
g
)
BfImpDist
4
f
⊃
g
2
,
3
,
MP
qed
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2024-08-03
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