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AndChopCommute
⊢
(
f
∧
f
1
)
⌢ g
≡
(
f
1
∧
f
)
⌢ g
AndChopCommute
Proof:
1
f
∧
f
1
≡
f
1
∧
f
Prop
2
(
f
∧
f
1
)
⌢ g
≡
(
f
1
∧
f
)
⌢ g
1
,
LeftChopEqvChop
qed
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2023-09-12
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