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AndChopB
⊢
(
f
∧
f
1
)
⌢ g
⊃
f
1
⌢ g
AndChopB
Proof:
1
f
∧
f
1
⊃
f
1
Prop
2
(
f
∧
f
1
)
⌢ g
⊃
f
1
⌢ g
1
,
LeftChopImpChop
qed
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2023-09-12
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