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BoxImpInferBoxImpBox
⊢
f
⊃
g
⇒ ⊢
f
⊃
g
BoxImpInferBoxImpBox
Proof:
1
f
⊃
g
Assump
2
(
f
⊃
g
)
1
,
BoxGen
3
(
f
⊃
g
)
⊃
(
f
⊃
g
)
VPTL
4
f
⊃
g
2
,
3
,
MP
qed
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2023-09-12
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