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DiamondEqvDiamond
⊢
f
≡
g
⇒ ⊢
f
≡
g
DiamondEqvDiamond
Proof:
1
f
≡
g
Assump
2
true
⌢ f
≡
true
⌢ g
1
,
RightChopEqvChop
3
f
≡
g
2
,
def. of
qed
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2023-09-12
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