DfImpDf

⊢ f ⊃ g ⇒ ⊢ f ⊃ g DfImpDf

Proof:

1
f ⊃ g
Assump
2
f ⌢ true ⊃ g ⌢ true
3
f ⊃ g
2, def. of 

qed

2024-08-03
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