BoxChopImpChop

⊢ (g ⊃ g1) ⊃ (f ⌢ g) ⊃ (f ⌢ g1) BoxChopImpChop

Proof:

1
finite ⊃ (f ⊃ f)
2
(f ⊃ f)
3
(f ⊃ f) ∧ (g ⊃ g1) ⊃ (f ⌢ g) ⊃ (f ⌢ g1)
4
(g ⊃ g1) ⊃ (f ⌢ g) ⊃ (f ⌢ g1)
2, 3,Prop

qed

2024-08-03
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