FBoxImpDist

(f g) f g FBoxImpDist

Proof:

1
(f g) (¬g ⊃ ¬f)
2
¬(¬g ⊃ ¬f) ⊃ ¬(f g)
1,Prop
3
(¬(¬g ⊃ ¬f) ⊃ ¬(f g))
4
(¬(¬g ⊃ ¬f) ⊃ ¬(f g))
(f g) (¬g ⊃ ¬f)
5
(f g) (¬g ⊃ ¬f)
3, 4,FLMP
6
(¬g ⊃ ¬f) f g
7
(f g) f g
5, 6,ImpChain

qed

2023-09-12
Contact | Home | ITL home | Course | Proofs | Algebra | FL
© 1996-2023